SQL Schema

Table: Transactions

+----------------+----------+
| Column Name    | Type     |
+----------------+----------+
| transaction_id | int      |
| day            | datetime |
| amount         | int      |
+----------------+----------+
transaction_id is the primary key for this table.
Each row contains information about one transaction.

Write an SQL query to report the IDs of the transactions with the maximum amount on their respective day. If in one day there are multiple such transactions, return all of them.

Return the result table in ascending order by transaction_id.

The query result format is in the following example:

Transactions table:
+----------------+--------------------+--------+
| transaction_id | day                | amount |
+----------------+--------------------+--------+
| 8              | 2021-4-3 15:57:28  | 57     |
| 9              | 2021-4-28 08:47:25 | 21     |
| 1              | 2021-4-29 13:28:30 | 58     |
| 5              | 2021-4-28 16:39:59 | 40     |
| 6              | 2021-4-29 23:39:28 | 58     |
+----------------+--------------------+--------+

Result table:
+----------------+
| transaction_id |
+----------------+
| 1              |
| 5              |
| 6              |
| 8              |
+----------------+
"2021-4-3"  --> We have one transaction with ID 8, so we add 8 to the result table.
"2021-4-28" --> We have two transactions with IDs 5 and 9. The transaction with ID 5 has an amount of 40, while the transaction with ID 9 has an amount of 21. We only include the transaction with ID 5 as it has the maximum amount this day.
"2021-4-29" --> We have two transactions with IDs 1 and 6. Both transactions have the same amount of 58, so we include both in the result table.
We order the result table by transaction_id after collecting these IDs.

First step - table creation

create Table Transactions1(
transaction_id int,
dayy TIMESTAMP,
amount int
);
insert into Transactions1 VALUES(8,'2021-4-3',57 ),
(9,'2021-4-28 08:47:25',21 ),
(1,'2021-4-29 13:28:30',58 ),
(5,'2021-4-28 16:39:59',40),
(6,'2021-4-29 23:39:28',58);

MYSQL SOLUTION:

WITH CTE AS (SELECT transaction_id,DATE_FORMAT(dayy,'%Y-%d-%m') as day1,amount from Transactions1 ),

cte2 as (SELECT *, max(amount)  OVER(PARTITION BY day1  ) as maximum_amount from CTE)
SELECT  transaction_id from cte2 WHERE amount = maximum_amount  order by transaction_id ;

OUTPUT